Trigamma function

Calculation

A double integral representation, as an alternative to the ones given above, may be derived from the series representation: : \psi_1(z) = \int_0^1!!\int_0^x\frac{x^{z-1}}{y(1 - x)},dy,dx using the formula for the sum of a geometric series. Integration over y yields: : \psi_1(z) = -\int_0^1\frac{x^{z-1}\ln{x}}{1-x},dx

An asymptotic expansion as a Laurent series can be obtained via the derivative of the asymptotic expansion of the digamma function: :\begin{align} \psi_1(z) &\sim {\operatorname{d}\over\operatorname{d}!z} \left(\ln z - \sum_{n=1}^\infty \frac{B_n}{nz^n}\right) \ &= \frac{1}{z} + \sum_{n=1}^\infty \frac{B_n}{z^{n+1}} = \sum_{n=0}^{\infty}\frac{B_n}{z^{n+1}} \ &= \frac{1}{z} + \frac{1}{2z^2} + \frac{1}{6z^3} - \frac{1}{30z^5} + \frac{1}{42z^7} - \frac{1}{30z^9} + \frac{5}{66z^{11}} - \frac{691}{2730z^{13}} + \frac{7}{6z^{15}} \cdots \end{align} where B**n is the nth Bernoulli number and we choose .

Recurrence and reflection formulae

The trigamma function satisfies the recurrence relation

: \psi_1(z + 1) = \psi_1(z) - \frac{1}{z^2}

and the reflection formula

: \psi_1(1 - z) + \psi_1(z) = \frac{\pi^2}{\sin^2 \pi z} ,

which immediately gives the value for z : \psi_1(\tfrac{1}{2})=\tfrac{\pi^2}{2} .

Special values

At positive integer values we have that : \psi_1(n) = \frac{\pi^2}{6} - \sum_{k=1}^{n-1} \frac{1}{k^2}, \qquad \psi_1(1) = \frac{\pi^2}{6}, \qquad \psi_1(2) = \frac{\pi^2}{6} - 1, \qquad \psi_1(3) = \frac{\pi^2}{6} - \frac{5}{4}.

At positive half integer values we have that : \psi_1\left(n+\frac12\right)=\frac{\pi^2}{2}-4\sum_{k=1}^n\frac{1}{(2k-1)^2}, \qquad \psi_1\left(\tfrac12\right) = \frac{\pi^2}{2}, \qquad \psi_1\left(\tfrac32\right) = \frac{\pi^2}{2} - 4 .

The trigamma function has other special values such as:

: \psi_1\left(\tfrac14\right) = \pi^2 + 8G

where G represents Catalan's constant.

There are no roots on the real axis of ψ1, but there exist infinitely many pairs of roots zn, for quickly and their imaginary part increases slowly logarithmic with n. For example, and are the first two roots with Im(z) 0.

Relation to the Clausen function

The digamma function at rational arguments can be expressed in terms of trigonometric functions and logarithm by the digamma theorem. A similar result holds for the trigamma function but the circular functions are replaced by Clausen's function. Namely, : \psi_1\left(\frac{p}{q}\right)=\frac{\pi^2}{2\sin^2(\pi p/q)}+2q\sum_{m=1}^{(q-1)/2}\sin\left(\frac{2\pi mp}{q}\right)\textrm{Cl}_2\left(\frac{2\pi m}{q}\right).

Appearance

The trigamma function appears in this sum formula:

: \sum_{n=1}^\infty\frac{n^2-\frac12}{\left(n^2+\frac12\right)^2}\left(\psi_1\bigg(n-\frac{i}{\sqrt{2}}\bigg)+\psi_1\bigg(n+\frac{i}{\sqrt{2}}\bigg)\right)= -1+\frac{\sqrt{2}}{4}\pi\coth\frac{\pi}{\sqrt{2}}-\frac{3\pi^2}{4\sinh^2\frac{\pi}{\sqrt{2}}}+\frac{\pi^4}{12\sinh^4\frac{\pi}{\sqrt{2}}}\left(5+\cosh\pi\sqrt{2}\right).

Notes

References

• Milton Abramowitz and Irene A. Stegun, Handbook of Mathematical Functions, (1964) Dover Publications, New York. . See section §6.4
• Eric W. Weisstein. Trigamma Function -- from MathWorld--A Wolfram Web Resource

References

1. (1991). "Structural properties of polylogarithms". American Mathematical Society.