From Surf Wiki (app.surf) — the open knowledge base
Square cupola
Cupola with octagonal base
Cupola with octagonal base
| Field | Value |
|---|---|
| image | square_cupola.png |
| type | Johnson |
| J – *J – J* | |
| faces | 4 triangles |
| 5 squares | |
| 1 octagon | |
| edges | 20 |
| vertices | 12 |
| symmetry | C_{4v} |
| vertex_config | 8 \times (3 \times 4 \times 8) + 4 \times (3 \times 4^3) |
| properties | convex |
| net | Square cupola symmetric net.svg |
J – J – J 5 squares 1 octagon
In geometry, the square cupola (sometimes called lesser dome) is a cupola with an octagonal base. In the case of all edges being equal in length, it is a Johnson solid, a convex polyhedron with regular faces. It can be used to construct many other polyhedrons, particularly other Johnson solids.
Properties
The square cupola has 4 triangles, 5 squares, and 1 octagon as their faces; the octagon is the base, and one of the squares is the top. If the edges are equal in length, the triangles and octagon become regular, and the edge length of the octagon is equal to the edge length of both triangles and squares. The dihedral angle between both square and triangle is approximately 144.7^\circ , that between both triangle and octagon is 54.7^\circ , that between both square and octagon is precisely 45^\circ , and that between two adjacent squares is 135^\circ . A convex polyhedron in which all the faces are regular is a Johnson solid, and the square cupola is enumerated as J_{4} , the fourth Johnson solid.
Given that the edge length of a , the surface area of a square cupola A can be calculated by adding the area of all faces: A = \left(7+2\sqrt{2}+\sqrt{3}\right)a^2 \approx 11.560a^2. Its height h , circumradius C , and volume V are: \begin{align} h &= \frac{\sqrt{2}}{2}a \approx 0.707a, \ C &= \left(\frac{1}{2}\sqrt{5+2\sqrt{2}}\right)a \approx 1.399a, \ V &= \left(1+\frac{2\sqrt{2}}{3}\right)a^3 \approx 1.943a^3. \end{align}
It has an axis of symmetry passing through the center of its both top and base, which is symmetrical by rotating around it at one-, two-, and three-quarters of a full-turn angle. It is also mirror-symmetric relative to any perpendicular plane passing through a bisector of the base. Therefore, it has pyramidal symmetry, the cyclic group C_{4v} of order 8.
References
References
This article was imported from Wikipedia and is available under the Creative Commons Attribution-ShareAlike 4.0 License. Content has been adapted to SurfDoc format. Original contributors can be found on the article history page.
Ask Mako anything about Square cupola — get instant answers, deeper analysis, and related topics.
Research with MakoFree with your Surf account
Create a free account to save articles, ask Mako questions, and organize your research.
Sign up freeThis content may have been generated or modified by AI. CloudSurf Software LLC is not responsible for the accuracy, completeness, or reliability of AI-generated content. Always verify important information from primary sources.
Report