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Shear force

Coplanar forces acting on the same body in opposite directions

Summary

Coplanar forces acting on the same body in opposite directions

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A crack or tear may develop in a body from parallel shearing forces acting in opposite directions at different points of the body. If the forces were aligned with each other, they would elongate or shorten the body, depending on their direction, rather than tear or crack it.

In solid mechanics, shearing forces are unaligned forces acting on one part of a body in a specific direction, and another part of the body in the opposite direction. When the forces are collinear (aligned with each other), they are called tension forces or compression forces. Shear force can also be defined in terms of planes: "If a plane is passed through a body, a force acting along this plane is called a shear force or shearing force."

Force required to shear steel

This section calculates the force required to cut a piece of material with a shearing action. The relevant information is the area of the material being sheared, i.e. the area across which the shearing action takes place, and the shear strength of the material. A round bar of steel is used as an example. The shear strength is calculated from the tensile strength using a factor which relates the two strengths. In this case 0.6 applies to the example steel, known as EN8 bright, although it can vary from 0.58 to 0.62 depending on application.

EN8 bright has a tensile strength of 800MPa and mild steel, for comparison, has a tensile strength of 400MPa.

To calculate the force to shear a 25 mm diameter bar of EN8 bright steel; : area of the bar in mm2 = (12.52)(π) ≈ 490.8mm2 : 0.8kN/mm2 × 490.8mm2 = 392.64kN ≈ 40tonne-force : 40tonne-force × 0.6 (to change force from tensile to shear) = 24tonne-force

When working with a riveted or tensioned bolted joint, the strength comes from friction between the materials bolted together. Bolts are correctly torqued to maintain the friction. The shear force only becomes relevant when the bolts are not torqued.

A bolt with property class 12.9 has a tensile strength of 1200MPa (1MPa = 1N/mm2) or 1.2kN/mm2 and the yield strength is 0.90 times tensile strength, 1080MPa in this case.

A bolt with property class 4.6 has a tensile strength of 400MPa (1MPa = 1N/mm2) or 0.4 kN/mm2 and yield strength is 0.60 times tensile strength, 240MPa in this case.

References

William A. Nash. (1 July 1998). "Schaum's Outline of Theory and Problems of Strength of Materials". McGraw-Hill Professional.

Wikipedia Source

This article was imported from Wikipedia and is available under the Creative Commons Attribution-ShareAlike 4.0 License. Content has been adapted to SurfDoc format. Original contributors can be found on the article history page.

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