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1840 United States presidential election in New York
A presidential election was held in New York from November 2–4, 1840 as part of the 1840 United States presidential election. Voters chose 42 representatives, or electors to the Electoral College, who voted for President and Vice President.
A presidential election was held in New York from November 2–4, 1840 as part of the 1840 United States presidential election. Voters chose 42 representatives, or electors to the Electoral College, who voted for President and Vice President.
New York voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won New York by a narrow margin of 3.00%.
| 1840 United States presidential election in New York | |||||||
|---|---|---|---|---|---|---|---|
| Whig | William Henry Harrison of Ohio | John Tyler of Virginia | 225,817 | 51.19% | 42 | 100.00% | |
| Democratic | Martin Van Buren of New York | Richard Mentor Johnson of Kentucky | 212,528 | 48.18% | 0 | 0.00% | |
| Liberty | James G. Birney of New York | Thomas Earle of Pennsylvania | 2,799 | 0.63% | 0 | 0.00% | |
| Total | 441,144 | 100.00% | 42 | 100.00% |
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Albany
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Broome
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Cattaraugus
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Cayuga
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Chenango
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Clinton
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Jefferson
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Kings
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Madison
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Oswego
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Rensselaer
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Richmond
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Saratoga
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Schenectady
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St. Lawrence
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Tompkins
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Ulster
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Wayne
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United States presidential elections in New York
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