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Schröder–Bernstein theorems for operator algebras
The Schröder–Bernstein theorem from set theory has analogs in the context of operator algebras. This article discusses such operator-algebraic results.
For von Neumann algebras
Suppose M is a von Neumann algebra and E, F are projections in M. Let ~ denote the Murray-von Neumann equivalence relation on M. Define a partial order « on the family of projections by E « F if E ~ F' * ≤ F. In other words, E « F if there exists a partial isometry U ∈ M such that UU = E and UU* ≤ F.
For closed subspaces M and N where projections PM and PN, onto M and N respectively, are elements of M, M « N if PM « PN.
The Schröder–Bernstein theorem states that if M « N and N « M, then M ~ N.
A proof, one that is similar to a set-theoretic argument, can be sketched as follows. Colloquially, N « M means that N can be isometrically embedded in M. So
:M = M_0 \supset N_0
where N0 is an isometric copy of N in M. By assumption, it is also true that, N, therefore N0, contains an isometric copy M1 of M. Therefore, one can write
:M = M_0 \supset N_0 \supset M_1.
By induction,
:M = M_0 \supset N_0 \supset M_1 \supset N_1 \supset M_2 \supset N_2 \supset \cdots .
It is clear that
:R = \cap_{i \geq 0} M_i = \cap_{i \geq 0} N_i.
Let
:M \ominus N \stackrel{\mathrm{def}}{=} M \cap (N)^{\perp}.
So
: M = \oplus_{i \geq 0} ( M_i \ominus N_i ) \quad \oplus \quad \oplus_{j \geq 0} ( N_j \ominus M_{j+1}) \quad \oplus R
and
: N_0 = \oplus_{i \geq 1} ( M_i \ominus N_i ) \quad \oplus \quad \oplus_{j \geq 0} ( N_j \ominus M_{j+1}) \quad \oplus R.
Notice
:M_i \ominus N_i \sim M \ominus N \quad \mbox{for all} \quad i.
The theorem now follows from the countable additivity of ~.
Representations of C*-algebras
There is also an analog of Schröder–Bernstein for representations of C*-algebras. If A is a C*-algebra, a representation of A is a *-homomorphism φ from A into L(H), the bounded operators on some Hilbert space H.
If there exists a projection P in L(H) where P φ(a) = φ(a) P for every a in A, then a subrepresentation σ of φ can be defined in a natural way: σ(a) is φ(a) restricted to the range of P. So φ then can be expressed as a direct sum of two subrepresentations φ = *φ' * ⊕ σ.
Two representations φ1 and φ2, on H1 and H2 respectively, are said to be unitarily equivalent if there exists a unitary operator U: H2 → H1 such that φ1(a)U = Uφ2(a), for every a.
In this setting, the Schröder–Bernstein theorem reads:
:If two representations ρ and σ, on Hilbert spaces H and G respectively, are each unitarily equivalent to a subrepresentation of the other, then they are unitarily equivalent.
A proof that resembles the previous argument can be outlined. The assumption implies that there exist surjective partial isometries from H to G and from G to H. Fix two such partial isometries for the argument. One has
:\rho = \rho_1 \simeq \rho_1 ' \oplus \sigma_1 \quad \mbox{where} \quad \sigma_1 \simeq \sigma.
In turn,
:\rho_1 \simeq \rho_1 ' \oplus (\sigma_1 ' \oplus \rho_2) \quad \mbox{where} \quad \rho_2 \simeq \rho .
By induction,
: \rho_1 \simeq \rho_1 ' \oplus \sigma_1 ' \oplus \rho_2' \oplus \sigma_2 ' \cdots \simeq ( \oplus_{i \geq 1} \rho_i ' ) \oplus ( \oplus_{i \geq 1} \sigma_i '),
and
: \sigma_1 \simeq \sigma_1 ' \oplus \rho_2' \oplus \sigma_2 ' \cdots \simeq ( \oplus_{i \geq 2} \rho_i ' ) \oplus ( \oplus_{i \geq 1} \sigma_i ').
Now each additional summand in the direct sum expression is obtained using one of the two fixed partial isometries, so
: \rho_i ' \simeq \rho_j ' \quad \mbox{and} \quad \sigma_i ' \simeq \sigma_j ' \quad \mbox{for all} \quad i,j ;.
This proves the theorem.
References
- B. Blackadar, Operator Algebras, Springer, 2006.
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