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2009 Knoxville Challenger – Doubles

SWE Andreas Siljeström RSA Izak van der Merwe

Main article: 2009 Knoxville Challenger

Kevin Anderson and G.D. Jones were the defending champions, but only Anderson tried to defend his title.

He partnered with Scott Lipsky. They were eliminated already in the first round by Raven Klaasen and Izak van der Merwe.

Martin Emmrich and Andreas Siljeström won this tournament, by defeating Klaasen and van der Merwe 7–5, 6–4 in the final.

Seeds

  1. RSA Kevin Anderson / USA Scott Lipsky (first round)
  2. PHI Treat Conrad Huey / IND Harsh Mankad (semifinals)
  3. AUS Kaden Hensel / AUS Adam Hubble (quarterfinals)
  4. USA Jesse Levine / USA Ryan Sweeting (quarterfinals)

Draw

Draw

| RD1-seed01=1 | RD1-team01=RSA K Anderson USA S Lipsky | RD1-score01-1=2 | RD1-score01-2=7 | RD1-score01-3=[5] | RD1-seed02= | RD1-team02=RSA R Klaasen RSA I van der Merwe | RD1-score02-1=6 | RD1-score02-2=65 | RD1-score02-3=[10]

| RD1-seed03= | RD1-team03=IND P Amritraj USA K Kim | RD1-score03-1=2 | RD1-score03-2=3 | RD1-score03-3= | RD1-seed04=WC | RD1-team04=USA D Sandgren AUS J-P Smith | RD1-score04-1=6 | RD1-score04-2=6 | RD1-score04-3=

| RD1-seed05=3 | RD1-team05=AUS K Hensel AUS A Hubble | RD1-score05-1=6 | RD1-score05-2=6 | RD1-score05-3= | RD1-seed06= | RD1-team06=CRO R Karanušić SLO G Žemlja | RD1-score06-1=1 | RD1-score06-2=3 | RD1-score06-3=

| RD1-seed07=WC | RD1-team07=USA C Parr USA T Paul | RD1-score07-1=4 | RD1-score07-2=63 | RD1-score07-3= | RD1-seed08= | RD1-team08=IND S Devvarman IND P Raja | RD1-score08-1=6 | RD1-score08-2=7 | RD1-score08-3=

| RD1-seed09=Q | RD1-team09=ESP A Brugués-Davi USA B Joelson | RD1-score09-1=0 | RD1-score09-2=2 | RD1-score09-3= | RD1-seed10= | RD1-team10=GER M Emmrich SWE A Siljeström | RD1-score10-1=6 | RD1-score10-2=6 | RD1-score10-3=

| RD1-seed11= | RD1-team11=USA N Monroe USA M Yani | RD1-score11-1=2 | RD1-score11-2=3 | RD1-score11-3= | RD1-seed12=4 | RD1-team12=USA J Levine USA R Sweeting | RD1-score12-1=6 | RD1-score12-2=6 | RD1-score12-3=

| RD1-seed13=LL | RD1-team13=USA B Battistone USA D Battistone | RD1-score13-1=3 | RD1-score13-2=2 | RD1-score13-3= | RD1-seed14= | RD1-team14=BUL G Dimitrov SWE F Prpic | RD1-score14-1=6 | RD1-score14-2=6 | RD1-score14-3=

| RD1-seed15=WC | RD1-team15=USA R Harrison USA R Rizza | RD1-score15-1=6 | RD1-score15-2=2 | RD1-score15-3=[8] | RD1-seed16=2 | RD1-team16=PHI TC Huey IND H Mankad | RD1-score16-1=2 | RD1-score16-2=6 | RD1-score16-3=[10]

| RD2-seed01= | RD2-team01=RSA R Klaasen RSA I van der Merwe | RD2-score01-1=64 | RD2-score01-2=6 | RD2-score01-3=[10] | RD2-seed02=WC | RD2-team02=USA D Sandgren AUS J-P Smith | RD2-score02-1=7 | RD2-score02-2=1 | RD2-score02-3=[4]

| RD2-seed03=3 | RD2-team03=AUS K Hensel AUS A Hubble | RD2-score03-1=3 | RD2-score03-2=1 | RD2-score03-3= | RD2-seed04= | RD2-team04=IND S Devvarman IND P Raja | RD2-score04-1=6 | RD2-score04-2=6 | RD2-score04-3=

| RD2-seed05= | RD2-team05=GER M Emmrich SWE A Siljeström | RD2-score05-1=5 | RD2-score05-2=6 | RD2-score05-3=[10] | RD2-seed06=4 | RD2-team06=USA J Levine USA R Sweeting | RD2-score06-1=7 | RD2-score06-2=4 | RD2-score06-3=[5]

| RD2-seed07= | RD2-team07=BUL G Dimitrov SWE F Prpic | RD2-score07-1=7 | RD2-score07-2=1 | RD2-score07-3=[4] | RD2-seed08=2 | RD2-team08=PHI TC Huey IND H Mankad | RD2-score08-1=65 | RD2-score08-2=6 | RD2-score08-3=[10]

| RD3-seed01= | RD3-team01=RSA R Klaasen RSA I van der Merwe | RD3-score01-1=6 | RD3-score01-2=6 | RD3-score01-3= | RD3-seed02= | RD3-team02=IND S Devvarman IND P Raja | RD3-score02-1=2 | RD3-score02-2=3 | RD3-score02-3=

| RD3-seed03= | RD3-team03=GER M Emmrich SWE A Siljeström | RD3-score03-1=6 | RD3-score03-2=7 | RD3-score03-3= | RD3-seed04=2 | RD3-team04=PHI TC Huey IND H Mankad | RD3-score04-1=3 | RD3-score04-2=63 | RD3-score04-3=

| RD4-seed01= | RD4-team01=RSA R Klaasen RSA I van der Merwe | RD4-score01-1=5 | RD4-score01-2=4 | RD4-score01-3= | RD4-seed02= | RD4-team02=GER M Emmrich SWE A Siljeström | RD4-score02-1=7 | RD4-score02-2=6 | RD4-score02-3=

References

Info: Wikipedia Source

This article was imported from Wikipedia and is available under the Creative Commons Attribution-ShareAlike 4.0 License. Content has been adapted to SurfDoc format. Original contributors can be found on the article history page.

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