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1999 Franklin Templeton Tennis Classic – Doubles
Tennis tournament
Tennis tournament
USA Richey Reneberg AUS Sandon Stolle Main article: 1999 Tennis Channel Open
Cyril Suk and Michael Tebbutt were the defending champions, but lost in the quarterfinals this year.
Justin Gimelstob and Richey Reneberg won the title, defeating Mark Knowles and Sandon Stolle 6–4, 6–7(4–7), 6–3 in the final.
Seeds
- RSA Ellis Ferreira / USA Rick Leach (first round)
- BAH Mark Knowles / AUS Sandon Stolle (final)
- AUS Joshua Eagle / AUS Patrick Rafter (first round)
- RSA David Adams / RSA John-Laffnie de Jager (first round)
Draw
Finals
| RD1-seed01=1 | RD1-team01=RSA E Ferreira USA R Leach | RD1-score01-1=6 | RD1-score01-2=6 | RD1-score01-3=6 | RD1-seed02= | RD1-team02=USA J Gimelstob USA R Reneberg | RD1-score02-1=1 | RD1-score02-2=7 | RD1-score02-3=7
| RD1-seed03= | RD1-team03=CZE C Suk USA M Tebbutt | RD1-score03-1=2 | RD1-score03-2=6 | RD1-score03-3=6 | RD1-seed04= | RD1-team04=ARG P Albano ARG D Orsanic | RD1-score04-1=6 | RD1-score04-2=4 | RD1-score04-3=2
| RD1-seed05=3 | RD1-team05=AUS J Eagle AUS P Rafter | RD1-score05-1=3 | RD1-score05-2=7 | RD1-score05-3=2 | RD1-seed06=LL | RD1-team06=RSA C Haggard MKD A Kitinov | RD1-score06-1=6 | RD1-score06-2=5 | RD1-score06-3=6
| RD1-seed07=Q | RD1-team07=USA J Palmer SCG N Zimonjić | RD1-score07-1=6 | RD1-score07-2=6 | RD1-score07-3= | RD1-seed08=WC | RD1-team08=AUS P Kilderry BEL X Malisse | RD1-score08-1=3 | RD1-score08-2=1 | RD1-score08-3=
| RD1-seed09= | RD1-team09=ESP F Roig ESP J Sánchez | RD1-score09-1=7 | RD1-score09-2=4 | RD1-score09-3=4 | RD1-seed10=WC | RD1-team10=USA B Bryan USA M Bryan | RD1-score10-1=6 | RD1-score10-2=6 | RD1-score10-3=6
| RD1-seed11= | RD1-team11=CZE J Novák CZE D Rikl | RD1-score11-1=7 | RD1-score11-2=3 | RD1-score11-3=7 | RD1-seed12=4 | RD1-team12=RSA D Adams RSA J-L de Jager | RD1-score12-1=6 | RD1-score12-2=6 | RD1-score12-3=5
| RD1-seed13=WC | RD1-team13=CAN J Robichaud USA C Woodruff | RD1-score13-1=7 | RD1-score13-2=4 | RD1-score13-3=6 | RD1-seed14= | RD1-team14=AUS A Florent AUS D Macpherson | RD1-score14-1=6 | RD1-score14-2=6 | RD1-score14-3=7
| RD1-seed15= | RD1-team15=USA D Johnson AUS P Tramacchi | RD1-score15-1=6 | RD1-score15-2=7 | RD1-score15-3=6 | RD1-seed16=2 | RD1-team16=BAH M Knowles AUS S Stolle | RD1-score16-1=7 | RD1-score16-2=6 | RD1-score16-3=7
| RD2-seed01= | RD2-team01=USA J Gimelstob USA R Reneberg | RD2-score01-1=7 | RD2-score01-2=6 | RD2-score01-3= | RD2-seed02= | RD2-team02=CZE C Suk USA M Tebbutt | RD2-score02-1=6 | RD2-score02-2=2 | RD2-score02-3=
| RD2-seed03=LL | RD2-team03=RSA C Haggard MKD A Kitinov | RD2-score03-1=6 | RD2-score03-2=2 | RD2-score03-3= | RD2-seed04=Q | RD2-team04=USA J Palmer SCG N Zimonjić | RD2-score04-1=7 | RD2-score04-2=6 | RD2-score04-3=
| RD2-seed05=WC | RD2-team05=USA B Bryan USA M Bryan | RD2-score05-1=1 | RD2-score05-2=6 | RD2-score05-3=6 | RD2-seed06= | RD2-team06=CZE J Novák CZE D Rikl | RD2-score06-1=6 | RD2-score06-2=4 | RD2-score06-3=4
| RD2-seed07= | RD2-team07=AUS A Florent AUS D Macpherson | RD2-score07-1=5 | RD2-score07-2=6 | RD2-score07-3=4 | RD2-seed08=2 | RD2-team08=BAH M Knowles AUS S Stolle | RD2-score08-1=7 | RD2-score08-2=4 | RD2-score08-3=6
| RD3-seed01= | RD3-team01=USA J Gimelstob USA R Reneberg | RD3-score01-1=6 | RD3-score01-2=6 | RD3-score01-3= | RD3-seed02=Q | RD3-team02=USA J Palmer SCG N Zimonjić | RD3-score02-1=3 | RD3-score02-2=3 | RD3-score02-3=
| RD3-seed03=WC | RD3-team03=USA B Bryan USA M Bryan | RD3-score03-1=2 | RD3-score03-2=6 | RD3-score03-3= | RD3-seed04=2 | RD3-team04=BAH M Knowles AUS S Stolle | RD3-score04-1=6 | RD3-score04-2=7 | RD3-score04-3=
| RD4-seed01= | RD4-team01=USA J Gimelstob USA R Reneberg | RD4-score01-1=6 | RD4-score01-2=64 | RD4-score01-3=6 | RD4-seed02=2 | RD4-team02=BAH M Knowles AUS S Stolle | RD4-score02-1=4 | RD4-score02-2=77 | RD4-score02-3=3
References
References
- "1999 Scottsdale". [[International Tennis Federation]].
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