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1998 Franklin Templeton Tennis Classic – Doubles

Tennis tournament


Summary

Tennis tournament

AUS Michael Tebbutt USA David Wheaton Main article: 1998 Franklin Templeton Tennis Classic

Luis Lobo and Javier Sánchez were the defending champions, but Sánchez did not participate this year. Lobo partnered Daniel Orsanic, losing in the first round.

Cyril Suk and Michael Tebbutt won the title, defeating Kent Kinnear and David Wheaton 4–6, 6–1, 7–6 in the final.

Seeds

  1. BAH Mark Knowles / AUS Mark Woodforde (quarterfinals)
  2. RSA Ellis Ferreira / USA Rick Leach (first round)
  3. USA Patrick Galbraith / AUS David Macpherson (first round)
  4. ARG Luis Lobo / ARG Daniel Orsanic (first round)

Draw

Draw

| RD1-seed01=1 | RD1-team01=BAH M Knowles AUS M Woodforde | RD1-score01-1=7 | RD1-score01-2=7 | RD1-score01-3= | RD1-seed02= | RD1-team02=ZIM W Black USA J Salzenstein | RD1-score02-1=6 | RD1-score02-2=6 | RD1-score02-3=

| RD1-seed03=WC | RD1-team03=GER N Kiefer SWE M Norman | RD1-score03-1=2 | RD1-score03-2=7 | RD1-score03-3=5 | RD1-seed04=WC | RD1-team04=BEL X Malisse ARM S Sargsian | RD1-score04-1=6 | RD1-score04-2=6 | RD1-score04-3=7

| RD1-seed05=3 | RD1-team05=USA P Galbraith AUS D Macpherson | RD1-score05-1=6 | RD1-score05-2=6 | RD1-score05-3= | RD1-seed06= | RD1-team06=RSA J-L de Jager RSA R Koenig | RD1-score06-1=7 | RD1-score06-2=7 | RD1-score06-3=

| RD1-seed07= | RD1-team07=ESP J Alonso ECU N Lapentti | RD1-score07-1=1 | RD1-score07-2=4 | RD1-score07-3= | RD1-seed08=Q | RD1-team08=USA K Kinnear USA D Wheaton | RD1-score08-1=6 | RD1-score08-2=6 | RD1-score08-3=

| RD1-seed09= | RD1-team09=USA L Jensen USA M Jensen | RD1-score09-1=6 | RD1-score09-2=3 | RD1-score09-3= | RD1-seed10= | RD1-team10=MEX D Roditi RSA B Talbot | RD1-score10-1=7 | RD1-score10-2=6 | RD1-score10-3=

| RD1-seed11= | RD1-team11=CAN S Lareau USA J Tarango | RD1-score11-1=6 | RD1-score11-2=7 | RD1-score11-3= | RD1-seed12=4 | RD1-team12=ARG L Lobo ARG D Orsanic | RD1-score12-1=3 | RD1-score12-2=6 | RD1-score12-3=

| RD1-seed13= | RD1-team13=USA D Randall USA J Waite | RD1-score13-1=6 | RD1-score13-2=6 | RD1-score13-3= | RD1-seed14=WC | RD1-team14=GER B Becker GER T Messmer | RD1-score14-1=2 | RD1-score14-2=0 | RD1-score14-3=

| RD1-seed15= | RD1-team15=CZE C Suk AUS M Tebbutt | RD1-score15-1=4 | RD1-score15-2=6 | RD1-score15-3=7 | RD1-seed16=2 | RD1-team16=RSA E Ferreira USA R Leach | RD1-score16-1=6 | RD1-score16-2=1 | RD1-score16-3=6

| RD2-seed01=1 | RD2-team01=BAH M Knowles AUS M Woodforde | RD2-score01-1=4 | RD2-score01-2=6 | RD2-score01-3=5 | RD2-seed02=WC | RD2-team02=BEL X Malisse ARM S Sargsian | RD2-score02-1=6 | RD2-score02-2=4 | RD2-score02-3=7

| RD2-seed03= | RD2-team03=RSA J-L de Jager RSA R Koenig | RD2-score03-1=6 | RD2-score03-2=3 | RD2-score03-3= | RD2-seed04=Q | RD2-team04=USA K Kinnear USA D Wheaton | RD2-score04-1=7 | RD2-score04-2=6 | RD2-score04-3=

| RD2-seed05= | RD2-team05=MEX D Roditi RSA B Talbot | RD2-score05-1=3 | RD2-score05-2=2 | RD2-score05-3= | RD2-seed06= | RD2-team06=CAN S Lareau USA J Tarango | RD2-score06-1=6 | RD2-score06-2=6 | RD2-score06-3=

| RD2-seed07= | RD2-team07=USA D Randall USA J Waite | RD2-score07-1=2 | RD2-score07-2=6 | RD2-score07-3=2 | RD2-seed08= | RD2-team08=CZE C Suk AUS M Tebbutt | RD2-score08-1=6 | RD2-score08-2=4 | RD2-score08-3=6

| RD3-seed01=WC | RD3-team01=BEL X Malisse ARM S Sargsian | RD3-score01-1=3 | RD3-score01-2=6 | RD3-score01-3= | RD3-seed02=Q | RD3-team02=USA K Kinnear USA D Wheaton | RD3-score02-1=6 | RD3-score02-2=7 | RD3-score02-3=

| RD3-seed03= | RD3-team03=CAN S Lareau USA J Tarango | RD3-score03-1=4 | RD3-score03-2=7 | RD3-score03-3=2 | RD3-seed04= | RD3-team04=CZE C Suk AUS M Tebbutt | RD3-score04-1=6 | RD3-score04-2=5 | RD3-score04-3=6

| RD4-seed01=Q | RD4-team01=USA K Kinnear USA D Wheaton | RD4-score01-1=6 | RD4-score01-2=1 | RD4-score01-3=6 | RD4-seed02= | RD4-team02=CZE C Suk AUS M Tebbutt | RD4-score02-1=4 | RD4-score02-2=6 | RD4-score02-3=7

Qualifying

Qualifying seeds

  1. USA Mark Keil / USA T. J. Middleton (qualifying competition)
  2. USA Kent Kinnear / USA David Wheaton (qualified)

Qualifiers

  1. USA Kent Kinnear / USA David Wheaton

Qualifying draw

| team-width=175

| RD1-seed1=1 | RD1-team1=USA Mark Keil USA T. J. Middleton | RD1-score1-1=7 | RD1-score1-2=6 | RD1-score1-3= | RD1-seed2=WC | RD1-team2=USA Darin Pleasant USA Andrew Stoner | RD1-score2-1=6 | RD1-score2-2=2 | RD1-score2-3=

| RD1-seed3= | RD1-team3=AUS Scott Draper USA Greg Van Emburgh | RD1-score3-1=4 | RD1-score3-2=6 | RD1-score3-3= | RD1-seed4=2 | RD1-team4=USA Kent Kinnear USA David Wheaton | RD1-score4-1=6 | RD1-score4-2=7 | RD1-score4-3=

| RD2-seed1=1 | RD2-team1=USA Mark Keil USA T. J. Middleton | RD2-score1-1=7 | RD2-score1-2=6 | RD2-score1-3=6 | RD2-seed2=2 | RD2-team2=USA Kent Kinnear USA David Wheaton | RD2-score2-1=6 | RD2-score2-2=7 | RD2-score2-3=7

Wikipedia Source

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