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1947–48 French Rugby Union Championship

French Rugby Competition

Field	Value
countries	France
champions	Lourdes
runnersup	Toulon
prevseason	1946–47
nextseason	1948–49

The 1947–48 French Rugby Union Championship of first division was contested by 40 clubs divided in 8 pools of five.

Thirty-two teams qualified from a federal selection and 8 from "Championnat d'Excellence".

The two better of each pool, for a total of 16 clubs was admitted to the play-off finals

The Championship was won by Lourdes who beat Toulon in the final.

Context

The 1948 Five Nations Championship was won by Ireland, France was second.
The "Coupe de France" was won by Castres that beat Lourdes in the final.

Qualification round

Teams in bold qualified for the "last 16" phase.

Last 16

Teams in bold qualified for the quarter-finals.

0	Romans	-	Castres	7 - 5

Quarter finals

Teams in bold qualified for the semi-finals.

	Vienne	-	Romans	10 - 3

Semi finals

	Toulon	-	Vienne	11 - 6

Final

Toulon	1 penalty de Bodrero

Info: Wikipedia Source

This article was imported from Wikipedia and is available under the Creative Commons Attribution-ShareAlike 4.0 License. Content has been adapted to SurfDoc format. Original contributors can be found on the article history page.

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