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1920 United States presidential election in Missouri
The 1920 United States presidential election in Missouri took place on November 2, 1920, as part of the 1920 United States presidential election. Voters chose 18 representatives, or electors, to the Electoral College, who voted for president and vice president.
The 1920 United States presidential election in Missouri took place on November 2, 1920, as part of the 1920 United States presidential election. Voters chose 18 representatives, or electors, to the Electoral College, who voted for president and vice president.
The Republican candidate, Warren G. Harding, won the state of Missouri and collected its 18 electoral votes. This election marked the first time since 1868 that a Republican carried Missouri with a majority of the vote.
| Party | Candidate | Votes | % |
|---|---|---|---|
| Republican | 727,162 | 54.56% | |
| Democratic | 574,799 | 43.13% | |
| Socialist | 20,242 | 1.52% | |
| Prohibition | 5,142 | 0.39% | |
| Farmer–Labor | 3,291 | 0.25% | |
| Socialist Labor | 2,164 | 0.16% | |
| 1,332,800 | 100% |
- United States presidential elections in Missouri
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