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1892 United States presidential election in Illinois
The 1892 United States presidential election in Illinois took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. State voters chose 24 electors to the Electoral College, which selected the president and vice president.
The 1892 United States presidential election in Illinois took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. State voters chose 24 electors to the Electoral College, which selected the president and vice president.
Illinois was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois. This marked the first time a Democratic candidate won Illinois since 1856 when James Buchanan carried the state. Illinois is one of the three states that voted Republican in both 1884 and 1888 but flipped to Cleveland in 1892, the others being California and Wisconsin.
| 1892 United States presidential election in Illinois | ||||
|---|---|---|---|---|
| Democratic | Grover Cleveland | 426,281 | 48.79% | 24 |
| Republican | Benjamin Harrison (incumbent) | 399,288 | 45.70% | 0 |
| Prohibition | John Bidwell | 25,871 | 2.96% | 0 |
| Populist | James B. Weaver | 22,207 | 2.54% | 0 |
| Totals | 873,647 | 100.00% | 24 | |
| Voter turnout | — |
- United States presidential elections in Illinois
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