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1876 United States presidential election in Nebraska
The 1876 United States presidential election in Nebraska took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
The 1876 United States presidential election in Nebraska took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Nebraska voted for the Republican nominee, Ohio Governor Rutherford B. Hayes, over the Democratic nominee, New York Governor Samuel J. Tilden by a margin of 29.4%.
With 64.70% of the popular vote, Nebraska would be Hayes' second strongest victory in terms of percentage in the popular vote after Vermont.
| 1876 United States presidential election in Nebraska | |||||||
|---|---|---|---|---|---|---|---|
| Republican | Rutherford B. Hayes of Ohio | William A. Wheeler of New York | 31,915 | 64.70% | 3 | 100.00% | |
| Democratic | Samuel J. Tilden of New York | Thomas A. Hendricks of Indiana | 17,413 | 35.30% | 0 | 0.00% | |
| Total | 49,328 | 100.00% | 3 | 100.00% |
- United States presidential elections in Nebraska
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