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1840 United States presidential election in Delaware

The 1840 United States presidential election in Delaware was held on November 10, 1840 as part of the 1840 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

The 1840 United States presidential election in Delaware was held on November 10, 1840 as part of the 1840 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Delaware voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Delaware by a margin of 10.1%.

Pledged to	Elector	Votes
Whig Party	William Henry Harrison	Peter F. Causey	5,967
Whig Party	William Henry Harrison	Benjamin Caulk	5,962
Whig Party	William Henry Harrison	Henry F. Hall	5,958
Democratic Party	Martin Van Buren	Thomas Jacobs	4,872
Democratic Party	Martin Van Buren	Christopher Vandergrift	4,871
Democratic Party	Martin Van Buren	Nehemiah Clarke	4,870
Write-in		Scattering	13

County	William Henry HarrisonWhig	Martin Van BurenDemocratic	Margin	Total votes cast
Kent	1,593	59.20%	1,095	40.69%	498	18.51%	2,691
New Castle	2,321	51.28%	2,195	48.50%	126	2.78%	4,526
Sussex	2,053	56.48%	1,582	43.52%	471	12.96%	3,635

New Castle
United States presidential elections in Delaware

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