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1836 United States presidential election in Delaware

The 1836 United States presidential election in Delaware was held on November 7, 1836 as part of the 1836 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

The 1836 United States presidential election in Delaware was held on November 7, 1836 as part of the 1836 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Delaware voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Delaware by a margin of 6.54%.

PartyPledged toElectorVotes
Whig PartyWilliam Henry HarrisonWilliam Dunning4,736
Whig PartyWilliam Henry HarrisonWilliam W. Morris4,736
Whig PartyWilliam Henry HarrisonHenry F. Hall4,731
Democratic PartyMartin Van BurenSamuel Paynter4,154
Democratic PartyMartin Van BurenBenjamin Potter4,152
Democratic PartyMartin Van BurenWilliam Seal4,152
Write-inScattering5
CountyWilliam Henry HarrisonWhigMartin Van BurenDemocraticMarginTotal votes cast
Kent1,20753.74%1,03946.26%1687.48%2,246
New Castle1,67147.88%1,81451.98%-143-4.10%3,490
Sussex1,85858.82%1,30141.18%55717.63%3,159
  • United States presidential elections in Delaware
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