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1832 United States presidential election in Rhode Island
The 1832 United States presidential election in Rhode Island took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
The 1832 United States presidential election in Rhode Island took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Rhode Island voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson. Clay won Rhode Island by a margin of 13.86%.
Jackson remains the only Democrat to win two consecutive terms without carrying Rhode Island either time.
| 1832 United States presidential election in Rhode Island | ||||
|---|---|---|---|---|
| National Republican | Henry Clay | 2,810 | 56.93% | 4 |
| Democratic | Andrew Jackson (incumbent) | 2,126 | 43.07% | 0 |
| Totals | 4,936 | 100.0% | 4 |
- United States presidential elections in Rhode Island
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